Anomalous Curves Part 2: padic niceties
$$ \def\F{\mathbb{F}} $$
$$ \def\Q{\mathbb{Q}} \def\F{\mathbb{F}} \def\Z{\mathbb{Z}} $$
This is part two of the series on anomalous curves. Go here for part one.
Today, I’ll give a sketch of the construction of Smart’s attack. This attack combines two elliptic curve tools:
 The reduction map of an elliptic curve over a local field.
 The formal group of an elliptic curve.
I will focus on the first one, and leave the details of the second for another post.
All the content is taken from these two sources:
 Silverman, The Arithmetic of Elliptic Curves,
 Monnerat, Computation of the discrete logarithm on elliptic curves of trace one.
Elliptic curves over local fields $p$adic numbers
Let $K$ be a local field, $R$ its ring of integers, and $k$ its residue field. If you want to continue with this level of generality, you can read Chapter VII of Silverman’s book. Otherwise, we’ll continue with $$ K = \Q_p, R = \Z_p, k = \F_p. $$ In number theory and cryptography, we start with a curve $\tilde{E}(\F_p)$ (we’ll see why the $\texttt{tilde}$ later). $\F_p$ is nice and all, but kind of restricted. $\Q_p$ on the other hand is a tractable field of characteristic $0$ with some nice properties. So it is natural to ask whether we can find a curve $E(\Q_p)$ with a way to go back and forth to $\tilde{E}(\F_p)$.
It turns out there is a very simple way to do so! In particular, there exists an exact sequence of groups $$ 0 \to E_1(\Q_p) \to E(\Q_p) \xrightarrow{\pi} \tilde{E}(\F_p) \to 0. $$ If $\tilde{E}: y^2 = x^3 + ax +b$, then $E: y^2 = x^3 + (a+O(p))x + (b+O(p))$. Now $\pi$ is rather simple. Given $[x:y:z]\in E(\Q_p)$, there exists $n$ such that $p^n x, p^n y, p^n z \in \Z_p$ and one of the three is not in $p\Z_p$. So without loss of generality, $P = [x:y:z]$ with $x,y,z\in \Z_p$ and one of them not in $p\Z_p$. Then, we use the canonical map $\Z_p\to\F_p$ to send $P$ to $\tilde{P}=[\tilde{x}, \tilde{y}, \tilde{z}]$, i.e., we just reduce all the coordinates modulo $p\Z_p$. It is easy to see that $\tilde{P} \in \tilde{E}$, and that $\pi\colon P \mapsto \tilde{P}$ is a group homomorphism.
Next, we state Hensel’s lifting lemma, a great tool to work with local fields.
Theorem (Hensel’s lemma for $\Z_p$): Let $F(x)\in \Z_p[x]$, $n\geq 1, a\in \Z_p$ with $F(a)\in p^n\Z_p$ and $F'(a)\notin p\Z_p$.
Then, there exists an (easily computable) $b\in \Z_p$ with $F(b)=0$ and $b  a \in p^n\Z_p$.
This result can be thought of as an analogue of Newton’s method on $\Z_p$, i.e., if we have a function $F$ that is close to zero on $a$, and has a nonzero derivative at that point, there is a root of $F$ close to $a$.
We can now prove the main theorem of this part:
Theorem (VII.2.1 in Silverman): $\pi$ is surjective. It is called the reduction map.
Proof: Let $\tilde{P}=(\tilde{x}, \tilde{y})\in \tilde{E}$. Let $y_0 = \tilde{y}$ seen as an element of $\Z_p$. Let $F(x) = x^3 + (a + O(p))x + (b+O(b))  y_0^2\in Z_p[x]$ (this is just the equation for the curve $E$ at $y_0$). $F$ is close to zero (a.k.a in $p\Z_p$) at points $x_0$ with $\tilde{x}_0=\tilde{x}$, with a nonzero derivative (since $\tilde{E}$ is nonsingular^{1}). We can thus apply Hensel’s lemma and find a point $\xi\in \Z_p$ with $F(\xi)=0$ and $\tilde{\xi}=\tilde{x}$. The point $P=(\xi, y_0)$ thus belongs to $E$ and maps to $\tilde{P}$ under $\pi$. Since $\tilde{P}$ was arbitrary, we conclude that $\pi$ is surjective.
The nice thing about this proof is that it gives a simple way to actually lift $\tilde{P}$ to $P$. In Sage, it’s as simple as:
tildeE = EllipticCurve(GF(p), [a, b]) # Arbitrary curve over Fp
E = EllipticCurve(Qp(p), [a, b]) # Lift of curve to Qp
tildeP = tildeE.random_point() # tildeP = tildeE(209429384434035 : 167128638250862 : 1)
P = E.lift_x(ZZ(tildeP.xy()[0])) # P = E(209429384434035 : 167128638250862 + O(p) : 1)
Removing the geometry
With this lift in hand, we’re close to the end of the construction!
We define subgroups of $E(\Q_p)$ as follows: $$ E_n(\Q_p) = \{ P \in E(\Q_p) \ \vert \ ord_p(x(P)) \leq 2n \} \cup \{\mathcal{O}\} $$ These subgroups can be thought of as increasingly tight neighborhoods of $\{\mathcal{O}\}$, or as equivalents to $p^n\Z_p \subset \Z_p$. This last analogy can be made precise by observing that if $P=(x,y) = [x:y:1]\in E_n(\Q_p)$, then $\frac{x}{y}\in p^n\Z_p$^{2}^{3}. In fact, this analogy can be made precise:
Theorem (VII.2.2 in Silverman): There is a group structure on $p\Z_p$ (that we denote $\hat{E}(p\Z_p)$) such that the map $$ E_1(\Q_p) \to \hat{E}(p\Z_p): [x:y:1] \mapsto \frac x y $$ is a group isomorphism, that also induces isomorphisms $E_n(\Q_p)\to \hat{E}(p^n\Z_p)$.
Finally, we can remove the geometry using the following result:
Theorem (IV.6.4 in Silverman): There is a isomorphism $$ \log_\mathcal{F}\colon \hat{E}(p\Z_p)\to p\Z_p $$ called the formal logarithm, where $p\Z_p$ on the right has the usual additive group structure. It also induces isomorphisms $\hat{E}(p^n\Z_p) \to p^n\Z_p$.
We will explore and prove these last two results in a coming post.
Putting it together
Let’s recap. We have our original curve $\tilde{E}(\F_p)$, a lift $E(\Q_p)$, and subgroups $E_n(\Q_p)$ where the DLP can be reduced to $p\Z_p$. Moreover, the exact sequence we showed above induces an isomorphism $$ E(\Q_p)/E_1(\Q_p) \to \tilde{E}(\F_p). $$ Note that we haven’t used the fact that $\#\tilde{E}(\F_p) = p$ yet, so all our previous constructions work for arbitrary curves. We now make use of it to break the DLP on $\tilde{E}(\F_p)$!
Since the DLP is simple in $E_1(\Q_p)$, we would win if we managed to lift points in $\tilde{E}(\F_p)$ to $E_1(\Q_p)$. But since $\#\tilde{E}(\F_p)=p$, we have $E(\Q_p)/E_1(\Q_p) \simeq \Z/p\Z$. Thus the multiplication by $p$ map $[p]$ sends $E(\Q_p)$ to $E_1(\Q_p)$.
Therefore, we have the following homomorphism $$ \phi\colon \tilde{E}(\F_p) \xrightarrow{\text{lift}} E(\Q_p) \xrightarrow{[p]} E_1(\Q_p) \to \hat{E}(p\Z_p)\xrightarrow{\log} p\Z_p \xrightarrow{\mod p^2}\Z/p\Z. $$ Moreover, we also have $E_1(\Q_p)/E_2(\Q_p) \simeq p\Z_p/p^2\Z_p \simeq \Z/p\Z$. So $[p]$ maps $E_1(\Q_p)$ to $E_2(\Q_p)$.
Therefore, $\phi$ restricted to $\mathcal{O}$ maps to $0\in \Z/p\Z$: $$ \phi\colon \mathcal{O} \xrightarrow{\text{lift}} E_1(\Q_p) \xrightarrow{[p]} E_2(\Q_p) \to \hat{E}(p^2\Z_p)\xrightarrow{\log} p^2\Z_p \xrightarrow{\mod p^2}0. $$ And its over! Concretely, for $\tilde{P}, \tilde{Q} \in \tilde{E}(\F_p)$, with $\tilde{Q}=[m]\tilde{P}$ for an unknown $m$, we have $Q[m]P\in E_1(\Q_p)\ (=\ker(\pi))$, so $\phi(\tilde{Q})=m\phi(\tilde{P})$ and we can solve the DLP in $\Z/p\Z$!
The nice thing is that it’s also very easy to code (taken from this post):
tildeE = EllipticCurve(GF(1019), [373, 837]) # Arbitrary curve over Fp
assert tildeE.order() == 1019 # The curve is anomalous
E = EllipticCurve(Qp(1019), [373, 837]) # Lift of curve to Qp
tildeP = tildeE.gens()[0]
tildeQ = 123 * tildeP
P = E.lift_x(ZZ(tildeP.xy()[0])) # Might have to take the other lift.
Q = E.lift_x(ZZ(tildeQ.xy()[0])) # Might have to take the other lift.
p_times_P = p*P
p_times_Q = p*Q
x_P, y_P = p_times_P.xy()
x_Q, y_Q = p_times_Q.xy()
phi_P = (x_P/y_P) # Map to Z/pZ
phi_Q = (x_Q/y_Q) # Map to Z/pZ
k = phi_Q/phi_P # Solve the discrete log in Z/pZ (aka do a division)
print Mod(k, 1019) # Prints 123
The most expensive operation is the multiplication by $p$, which takes $O(\log p)$ time.
It is interesting to see where this attack fails for nonanomalous curves. The only place we used that $\#\tilde{E}(\F_p)=p$ was to show that $[p]$ maps $E(\Q_p)$ to $E_1(\Q_p)$. So this should be wrong in general^{4}:
tildeE = EllipticCurve(GF(1019), [373, 837]) # Anomalous curve over Fp
assert tildeE.order() == 1019 # The curve is anomalous
E = EllipticCurve(Qp(1019), [373, 837]) # Lift of curve to Qp
P = E.lift_x(ZZ(randint(1, p))) # Random point in E. Might fail.
print p*P # (O(p^2) : O(p^3) : 1) in E_1(Q_p).
tildeE = EllipticCurve(GF(1019), [373, 839]) # Arbitrary curve over Fp
assert tildeE.order() != 1019 # The curve is NOT anomalous
E = EllipticCurve(Qp(1019), [373, 839]) # Lift of curve to Qp
P = E.lift_x(ZZ(randint(1, p))) # Random point in E. Might fail.
print p*P # (O(1) : O(1) : 1) NOT in E_1(Q_p).
So most curves are safe against this attack.
Next time, we’ll explore the concept of formal groups and prove the two theorems we used to remove the geometry from the problem.

Actually, it could be that the derivative is zero, but then the partial derivate $\partial/\partial y$ is nonzero and we can change the proof by switching all $x$’s to $y$’s. ↩︎

Here we use the fact that $[x:y:1]\in E(\Q_p)$ are of the form $[O(p^{2n}), O(p^{3n}), 1]$. ↩︎

We note that $E_1(\Q_p)$ was also previously defined as the kernel of $\pi$. Using this remark, it is clear that the two definitions are equivalent. ↩︎

Note that $[p]: E_n(\Q_p) \to E_{n+1}(\Q_p)$ remains true for all curves since $E_n(\Q_p)/E_{n+1}(\Q_p) \simeq p^n\Z_p/p^{n+1}\Z_p \simeq \Z/p\Z$ is a general result. ↩︎